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NEET PHYSICSEasy

Two bodies of masses m1m_1 and m2m_2 have equal kinetic energies. If p1p_1 and p2p_2 are their respective momenta, then the ratio p1:p2p_1 : p_2 is equal to:

A

m1:m2m_1:m_2

B

m2:m1m_2:m_1

C

m1:m2\sqrt{m_1}:\sqrt{m_2}

D

m12:m22m_1^2:m_2^2

Step-by-Step Solution

The kinetic energy KK of a body is related to its linear momentum pp and mass mm by the formula K=p22mK = \frac{p^2}{2m}. Given that the two bodies have equal kinetic energies (K1=K2K_1 = K_2): p122m1=p222m2\frac{p_1^2}{2m_1} = \frac{p_2^2}{2m_2} p12p22=m1m2\frac{p_1^2}{p_2^2} = \frac{m_1}{m_2} Taking the square root on both sides: p1p2=m1m2\frac{p_1}{p_2} = \frac{\sqrt{m_1}}{\sqrt{m_2}} Thus, the ratio of their momenta p1:p2p_1 : p_2 is equal to m1:m2\sqrt{m_1} : \sqrt{m_2}.

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