Browse and search thousands of solved questions for your preparation.
Free questions with full explanations — locked behind signup to protect quality.
Consider the following List-I and List-II: **List-I (Molecule)** (a) $PCl_{5}$ (b) $SF_{6}$ (c) $BeCl_{2}$ (d) $NH_{3}$ **List-II (Shape or geometry)** (i) Trigonal planar (ii) Octahedral (iii) Linear (iv) Trigonal pyramidal Identify the **wrong** match from the given pairs:
Among the following, isoelectronic species are:
The pairs of species of oxygen and their magnetic behaviours are given below. Which of the following represents the correct description?
The most preferred structure among the following with the lowest energy for $SO_{3}$ is:
The correct order of dissociation energy of $N_{2}$ and $N_{2}^{+}$ is:
A molecule that cannot exist is:
The structures of beryllium chloride in solid state and vapour phase, are :
Identify the incorrect statement among the following options:
Amongst the following, which one will have maximum 'lone pair - lone pair' electron repulsions?
Which one of the following is the correct order of decreasing bond enthalpies for the given species?
Which of the following set of molecules will have zero dipole moment?
Which one of the following pairs of species have the same bond order?
Predict the correct order among the following.
The correct bond order in the following species is:
Decreasing order of stability of $\text{O}_2$, $\text{O}_2^-$, $\text{O}_2^+$ and $\text{O}_2^{2-}$ is:
Paramagnetic species among the following is:
The correct order of solubility in an aqueous medium is:
Considering the state of hybridisation of carbon atoms, find out the molecule among the following which is linear.
Identify the incorrect match. Name: (a) Unnilunium, (b) Unniltrium, (c) Unnilhexium, (d) Unununium. IUPAC Official Name: (i) Mendelevium, (ii) Lawrencium, (iii) Seaborgium, (iv) Darmstadtium.
The state of hybridisation of carbons marked 2, 3, 5 and 6 in the following hydrocarbon are, respectively: $\overset{6}{\text{CH}_3}-\overset{5}{\text{CH}}=\overset{4}{\text{CH}}-\overset{3}{\text{CH}_2}-\overset{2}{\text{C}}\equiv\overset{1}{\text{CH}}$