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NEET CHEMISTRYElectrochemistryMedium

Question

In producing chlorine through electrolysis, 100 W power at 125 V is being consumed. The liberation of chlorine per min is: (ECE of chlorine is 0.367×106 kg/C0.367 \times 10^{-6} \text{ kg/C})

A

17.6 mg

B

21.3 mg

C

24.3 mg

D

13.6 mg

Step-by-Step Solution

Given: Power (PP) = 100 W Voltage (VV) = 125 V Time (tt) = 1 min = 60 s Electrochemical Equivalent (ZZ) = 0.367×106 kg C1=0.367 mg C10.367 \times 10^{-6} \text{ kg C}^{-1} = 0.367 \text{ mg C}^{-1}

First, we find the current (II) using the relation P=VIP = VI: I=PV=100125=0.8 AI = \frac{P}{V} = \frac{100}{125} = 0.8 \text{ A}

Now, calculate the total charge (QQ) passed in 1 minute (60 seconds): Q=I×t=0.8 A×60 s=48 CQ = I \times t = 0.8 \text{ A} \times 60 \text{ s} = 48 \text{ C}

According to Faraday's First Law of Electrolysis, the mass (mm) liberated is given by: m=Z×Qm = Z \times Q m=(0.367×106 kg C1)×48 Cm = (0.367 \times 10^{-6} \text{ kg C}^{-1}) \times 48 \text{ C} m=17.616×106 kgm = 17.616 \times 10^{-6} \text{ kg}

Converting kilograms to milligrams: m=17.616×106×106 mg17.6 mgm = 17.616 \times 10^{-6} \times 10^{6} \text{ mg} \approx 17.6 \text{ mg}

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Electrochemistry. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYElectrochemistryproducingchlorinethroughelectrolysisconsumed

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