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The major product H of the given reaction sequence is: $$ CH_3-CH_2-CO-CH_3 \xrightarrow{HCN} G \xrightarrow{95\% H_2SO_4, \Delta} H $$
The first ionization enthalpies of elements X and Y are 419 kJ mol⁻¹ and 590 kJ mol⁻¹, respectively and the second ionization enthalpies of X and Y are 3069 kJ mol⁻¹ and 1145 kJ mol⁻¹, respectively. The correct statement is:
Given is a reaction for your reference: The final product [C] is:
The first ionization potential of Be and B will be:
The correct order of 1st IP (ionization potential) among the following elements Be, B, C, N, O is:
The correct order of ionic radii is:
Identify Z in the following reaction: $CH_3CH_2CH=CH_2 \xrightarrow{B_2H_6} \xrightarrow{H_2O, H_2O_2, OH^-} Z$
The reagents with which glucose does not react to give the corresponding test/products are: A. Tollen's reagent B. Schiff's reagent C. $\text{HCN}$ D. $\text{NH}_2\text{OH}$ E. $\text{NaHSO}_3$ Choose the correct option:
For the second-period elements, the correct increasing order of first ionisation enthalpy is:
Consider the following reaction sequence: $$\text{Ethanol} \xrightarrow{PBr_3} X \xrightarrow{\text{Alc. KOH}} Y \xrightarrow[(ii) H_2O, \Delta]{(i) H_2SO_4, \text{room temp.}} Z$$ The product Z is:
The incorrect match among the following is:
The sequence of ionic mobility in aqueous solution is:
The correct statement among the following is:
Identify the final product [D] obtained in the following sequence of reactions: [Reaction Sequence Missing]
The most acidic compound among the following is:
Match List-I (Elements) with List-II (Atomic radii (pm)): | List-I (Elements) | List-II (Atomic radii in pm) | | :--- | :--- | | (a) Oxygen | (i) 88 | | (b) Carbon | (ii) 74 | | (c) Boron | (iii) 66 | | (d) Nitrogen | (iv) 77 |
The correct sequence given below contains neutral, acidic, basic, and amphoteric oxide each, respectively is:
Incorrect statement among the following is:
Order of acidic strength of the following compounds will be: [Note: Specific structures for A, B, C, and D were not provided in the input, but typically involve Phenol and substituted phenols]
The product 'D' in the following reaction is: $$CH_3CN \xrightarrow{H_3O^+} A \xrightarrow{NH_3, \Delta} B \xrightarrow{NaOBr} C \xrightarrow{NaNO_2/HCl} D$$