NEET Aldehydes Ketones and Carboxylic Acids — Set 10

Question 1

Arrange in increasing order of reactivity with $ \ce{HCN} $: $ \ce{CH3CHO} $, $ \ce{CH3COCH3} $, $ \ce{C6H5CHO} $.

Accepted Answer

Reactivity with $ \ce{HCN} $ decreases with steric hindrance and increases with electrophilicity: $ \ce{CH3COCH3} $ (ketone) < $ \ce{C6H5CHO} $ (aromatic aldehyde) < $ \ce{CH3CHO} $ (aliphatic aldehyde).

Question 2

What is the product when benzaldehyde reacts with $ \ce{NaOH} $ in the Cannizzaro reaction?

Accepted Answer

Benzaldehyde ($ \ce{C6H5CHO} $) lacks α-hydrogens, so it undergoes Cannizzaro reaction, forming benzyl alcohol ($ \ce{C6H5CH2OH} $) and benzoate.

Question 3

What is the product when propanoic acid is treated with $ \ce{SOCl2} $?

Accepted Answer

Propanoic acid ($ \ce{CH3CH2COOH} $) reacts with $ \ce{SOCl2} $ to form propanoyl chloride ($ \ce{CH3CH2COCl} $).

NEET Chemistry: Aldehydes Ketones and Carboxylic Acids — Practice Set 10

Q1. Arrange in increasing order of reactivity with \( \ce{HCN} \): \( \ce{CH3CHO} \), \( \ce{CH3COCH3} \), \( \ce{C6H5CHO} \).

Q2. What is the product when benzaldehyde reacts with \( \ce{NaOH} \) in the Cannizzaro reaction?

Q3. What is the product when propanoic acid is treated with \( \ce{SOCl2} \)?

Q4. Which compound is formed when benzoic acid reacts with \( \ce{SOCl2} \)?

Q5. Which ketone reacts with itself under basic conditions to form a nine-carbon β-hydroxy ketone?

Q6. Which compound forms a seven-carbon aldehyde via aldol condensation with ethanal?

Q7. What is the common name of \( \ce{CH3COCH3} \)?

Q8. What is the product when methanal undergoes Cannizzaro reaction?

Q9. Which method reduces a ketone to a methylene group?

Q10. What is the common name of \( \ce{HCOOH} \)?