NEET Aldehydes Ketones and Carboxylic Acids — Set 4

Question 1

What is the product when heptan-4-one is reduced with $ \ce{NaBH4} $?

Accepted Answer

$ \ce{NaBH4} $ reduces heptan-4-one ($ \ce{CH3CH2CH2COCH2CH2CH3} $) to heptan-4-ol ($ \ce{CH3CH2CH2CH(OH)CH2CH2CH3} $), a secondary alcohol.

Question 2

Which reagent distinguishes between ethanal and benzaldehyde?

Accepted Answer

Fehling’s solution oxidizes aliphatic aldehydes like ethanal ($ \ce{CH3CHO} $) to form a red precipitate, but does not react with aromatic aldehydes like benzaldehyde ($ \ce{C6H5CHO} $).

Question 3

What is the product when 2-methylpropanal undergoes Cannizzaro reaction?

Accepted Answer

2-Methylpropanal ($ \ce{(CH3)2CHCHO} $) has no α-hydrogens, so it undergoes Cannizzaro reaction, forming 2-methylpropanol ($ \ce{(CH3)2CHCH2OH} $) and 2-methylpropanoate.

NEET Chemistry: Aldehydes Ketones and Carboxylic Acids — Practice Set 4

Q1. What is the product when heptan-4-one is reduced with \( \ce{NaBH4} \)?

Q2. Which reagent distinguishes between ethanal and benzaldehyde?

Q3. What is the product when 2-methylpropanal undergoes Cannizzaro reaction?

Q4. What is the IUPAC name of \( \ce{CH3CH2CH2CHO} \)?

Q5. Which aldehyde forms an eight-carbon unsaturated carbonyl compound via self-aldol condensation?

Q6. Which compound does not undergo aldol condensation?

Q7. Which compound is formed by the ozonolysis of 3-methyl-1-butene followed by hydrolysis?

Q8. Which reaction converts propanal to propan-1-ol?

Q9. What is the product when cyclohexanone reacts with \( \ce{NaBH4} \)?

Q10. Which reaction converts \( \ce{CH3CH2CHO} \) to \( \ce{CH3CH=CHCHO} \)?