NEET Amines — Set 2

Question 1

The product of $ \ce{CH3CH2CH2CONH2} $ undergoing Hoffmann bromamide reaction is:

Accepted Answer

Butanamide ($ \ce{CH3CH2CH2CONH2} $) is converted to propan-1-amine ($ \ce{CH3CH2CH2NH2} $) by losing one carbon in the Hoffmann reaction, as per the PDF.

Question 2

Which amine has the least number of carbon atoms in its alkyl group?

Accepted Answer

Methylamine ($ \ce{CH3NH2} $) has one carbon in its alkyl group, the least among the options, as per the PDF’s classification.

Question 3

Which reagent acetylates the amino group of aniline?

Accepted Answer

Acetic anhydride ($ \ce{(CH3CO)2O} $) reacts with aniline to form acetanilide by acetylating the $ \ce{-NH2} $ group, as described in the PDF’s chemical properties.

NEET Chemistry: Amines — Practice Set 2

Q1. The product of \( \ce{CH3CH2CH2CONH2} \) undergoing Hoffmann bromamide reaction is:

Q2. Which amine has the least number of carbon atoms in its alkyl group?

Q3. Which reagent acetylates the amino group of aniline?

Q4. The solubility of amines in water decreases with:

Q5. The reaction of \( \ce{CH3CH2NH2} \) with excess \( \ce{CH3Cl} \) yields:

Q6. A compound \( X \) on reduction with \( \ce{H2/Ni} \) gives \( \ce{CH3CH2NH2} \). \( X \) is:

Q7. Which reaction produces a foul-smelling isocyanide from \( \ce{CH3NH2} \)?

Q8. How many carbon atoms are in the product of \( \ce{CH3CH2NH2} \) with \( \ce{CH3COCl} \)?

Q9. The reaction of \( \ce{CH3CH2Cl} \) with excess \( \ce{NH3} \) primarily yields:

Q10. Which amine forms a product with a benzene ring when reacted with \( \ce{H2SO4} \) at 453-473 K?