NEET Amines — Set 8

Question 1

Which of the following does not form a salt with dilute HCl?

Accepted Answer

Tertiary amines like $ \ce{(CH3CH2)3N} $ form salts with HCl due to the lone pair on nitrogen. However, $ \ce{CH3CONH2} $ (an amide) is not basic enough to form a salt, as per the PDF.

Question 2

Which amine is produced from $ \ce{CH3CH2CONH2} $ via Hoffmann bromamide reaction?

Accepted Answer

Propanamide ($ \ce{CH3CH2CONH2} $) loses one carbon in the Hoffmann reaction to form ethylamine ($ \ce{CH3CH2NH2} $), as per the PDF.

Question 3

The product of $ \ce{C6H5NH2} $ with $ \ce{CH3CH2COCl} $ is:

Accepted Answer

Aniline ($ \ce{C6H5NH2} $) reacts with propanoyl chloride ($ \ce{CH3CH2COCl} $) to form N-phenylpropanamide ($ \ce{C6H5NHCOCH2CH3} $), as per the PDF’s acylation.

NEET Chemistry: Amines — Practice Set 8

Q1. Which of the following does not form a salt with dilute HCl?

Q2. Which amine is produced from \( \ce{CH3CH2CONH2} \) via Hoffmann bromamide reaction?

Q3. The product of \( \ce{C6H5NH2} \) with \( \ce{CH3CH2COCl} \) is:

Q4. The boiling point trend for amines of similar molecular weight is:

Q5. The bond angle around nitrogen in \( \ce{(CH3CH2)2NH} \) is closest to:

Q6. Which amine forms a precipitate insoluble in NaOH with benzenesulphonyl chloride?

Q7. The amine produced from \( \ce{CH3CONH2} \) via Hoffmann bromamide reaction is:

Q8. Which amine does not produce \( \ce{N2} \) gas with \( \ce{HNO2} \)?

Q9. Which reagent is used to distinguish primary amines from secondary amines by forming a soluble product in alkali?

Q10. An amine \( X \) forms a precipitate with \( \ce{Br2} \) water but not with \( \ce{HNO2} \). \( X \) is: