NEET Chemistry: Amines — MCQ Test 2

Q6. A compound \( X \) on reduction with \( \ce{H2/Ni} \) gives \( \ce{CH3CH2NH2} \). \( X \) is:

Q7. Which reaction produces a foul-smelling isocyanide from \( \ce{CH3NH2} \)?

Q8. How many carbon atoms are in the product of \( \ce{CH3CH2NH2} \) with \( \ce{CH3COCl} \)?

Q9. The reaction of \( \ce{CH3CH2Cl} \) with excess \( \ce{NH3} \) primarily yields:

Q10. Which amine forms a product with a benzene ring when reacted with \( \ce{H2SO4} \) at 453-473 K?

NEET Chemistry — Amines

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1Question 1 of 10
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The product of \( \ce{CH3CH2CH2CONH2} \) undergoing Hoffmann bromamide reaction is:

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About this NEET MCQ Test

This page provides a free online MCQ test for NEET Chemistry preparation, focusing specifically on the chapter Amines. It contains 10 carefully selected multiple-choice questions (MCQs) designed to test your conceptual understanding and exam readiness.

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Key concepts covered in this specific test include Undergoing, Hoffmann, Bromamide, Reaction, Acetylates, and Solubility.

Taking these timed MCQ tests helps you simulate the real NEET exam environment. Detailed step-by-step explanations are provided for every question to help you learn from your mistakes and strengthen your fundamentals.

Preview of Questions in this Test

Q1. The product of \( \ce{CH3CH2CH2CONH2} \) undergoing Hoffmann bromamide reaction is:

  • A. \( \ce{CH3CH2NH2} \)
  • B. \( \ce{CH3CH2CH2NH2} \)
  • C. \( \ce{CH3NH2} \)
  • D. \( \ce{(CH3)2NH} \)

Q2. Which amine has the least number of carbon atoms in its alkyl group?

  • A. \( \ce{CH3CH2NH2} \)
  • B. \( \ce{(CH3CH2)2NH} \)
  • C. \( \ce{CH3NH2} \)
  • D. \( \ce{CH3CH2CH2NH2} \)

Q3. Which reagent acetylates the amino group of aniline?

  • A. \( \ce{CH3Cl} \)
  • B. \( \ce{(CH3CO)2O} \)
  • C. \( \ce{CH3COOH} \)
  • D. \( \ce{CHCl3} \)

Q4. The solubility of amines in water decreases with:

  • A. Decrease in molecular weight
  • B. Increase in hydrogen bonding
  • C. Decrease in alkyl chain length
  • D. Increase in alkyl chain length

Q5. The reaction of \( \ce{CH3CH2NH2} \) with excess \( \ce{CH3Cl} \) yields:

  • A. \( \ce{CH3CH2NHCH3} \)
  • B. \( \ce{(CH3)3N} \)
  • C. \( \ce{CH3CH2CH2NH2} \)
  • D. \( \ce{CH3CH2N(CH3)2} \)

+ 5 more questions in the actual test

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