Q1. The emf of a cell \( Fe(s) | Fe^{2+}(0.001 \, M) || Cu^{2+}(0.1 \, M) | Cu(s) \) at 298 K is (Given: \( E^\circ_{Fe^{2+}/Fe} = -0.44 \, V \), \( E^\circ_{Cu^{2+}/Cu} = 0.34 \, V \))?
- A. 0.78 V
- B. 0.839 V
- C. 0.721 V
- D. 0.90 V
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Sign In FreeThe emf of a cell \( Fe(s) | Fe^{2+}(0.001 \, M) || Cu^{2+}(0.1 \, M) | Cu(s) \) at 298 K is (Given: \( E^\circ_{Fe^{2+}/Fe} = -0.44 \, V \), \( E^\circ_{Cu^{2+}/Cu} = 0.34 \, V \))?