Q1. The resistance of a conductivity cell with 0.02 M KCl solution is 400 Ω, and its conductivity is 0.0025 S cm\(^{-1}\). What is the cell constant?
- A. 0.25 cm\(^{-1}\)
- B. 2.5 cm\(^{-1}\)
- C. 1.0 cm\(^{-1}\)
- D. 0.5 cm\(^{-1}\)
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Sign In FreeThe resistance of a conductivity cell with 0.02 M KCl solution is 400 Ω, and its conductivity is 0.0025 S cm\(^{-1}\). What is the cell constant?