Q1. The \( K_a \) of \( \ce{HCN} \) is \( 6.2 \times 10^{-10} \). What is the \( K_b \) of \( \ce{CN-} \) at 298 K?
- A. \( 6.2 \times 10^{-10} \)
- B. \( 1.0 \times 10^{-14} \)
- C. \( 3.1 \times 10^{-5} \)
- D. \( 1.61 \times 10^{-5} \)
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Sign In FreeThe \( K_a \) of \( \ce{HCN} \) is \( 6.2 \times 10^{-10} \). What is the \( K_b \) of \( \ce{CN-} \) at 298 K?