Q1. The \( K_a \) of \( \ce{HNO2} \) is \( 4.5 \times 10^{-4} \). What is the \( K_b \) of \( \ce{NO2-} \) at 298 K?
- A. \( 4.5 \times 10^{-4} \)
- B. \( 1.0 \times 10^{-14} \)
- C. \( 5.0 \times 10^{-10} \)
- D. \( 2.22 \times 10^{-11} \)
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Sign In FreeThe \( K_a \) of \( \ce{HNO2} \) is \( 4.5 \times 10^{-4} \). What is the \( K_b \) of \( \ce{NO2-} \) at 298 K?