NEET Chemistry: Solutions — Practice Set 9

Q1. A 0.5 M solution of K₂SO₄ (molar mass = 174 g/mol) has a density of 1.15 g/mL. What is the mass of the solute in 300 mL of this solution?

Q2. A solution lowers the vapor pressure of a solvent from 40 mm Hg to 38 mm Hg. What is the mole fraction of the solute?

Q3. The solubility of a gas in a solvent follows Henry’s law with a constant of 180 bar. If the partial pressure is increased by 50% from 6 bar, what is the new mole fraction of the gas?

Q4. What is the molar mass of a solute if 3 g of it in 200 mL of solution produces an osmotic pressure of 0.738 atm at 27°C? (\( R = 0.0821 \, \text{L atm mol}^{-1} \text{K}^{-1} \))

Q5. A 0.1 M solution of K₃PO₄ (assuming complete dissociation) has an osmotic pressure of 0.984 atm at a certain temperature. What is the temperature? (\( R = 0.0821 \, \text{L atm mol}^{-1} \text{K}^{-1} \))

Q6. A solution of 18 g of glucose (molar mass = 180 g/mol) in 1 kg of water freezes at -0.186°C. What is the \( K_f \) of water?

Q7. A 0.3 M solution of Na₂SO₄ (assuming complete dissociation) has an osmotic pressure of 2.214 atm at a certain temperature. What is the temperature? (\( R = 0.0821 \, \text{L atm mol}^{-1} \text{K}^{-1} \))

Q8. A solute dissociates into 3 ions with a van’t Hoff factor of 2.4. What is the degree of dissociation?

Q9. A solution reduces the vapor pressure of a solvent from 28 mm Hg to 26 mm Hg. What is the mole fraction of the solute?

Q10. The vapor pressure of pure water is 30 mm Hg at a certain temperature. A solution with a non-volatile solute has a vapor pressure of 28.5 mm Hg. If the solute’s molality is 0.5 mol/kg, what is the mass of water in the solution?

ChemistrySolutions

Set 9 of 20

15:00

Sign in to save your score and view detailed explanations

Sign In Free
1Question 1 of 10
Medium

A 0.5 M solution of K₂SO₄ (molar mass = 174 g/mol) has a density of 1.15 g/mL. What is the mass of the solute in 300 mL of this solution?