NEET Chemistry: Some Basic Concepts Of Chemistry — MCQ Test 3

Q6. What is the mass percentage of \( \ce{NH3} \) in a solution made by dissolving 3.4 g of \( \ce{NH3} \) in 16.6 g of water? (Molar mass: \( \ce{NH3} \) = 17 g/mol)

Q7. A 0.56 g sample of a hydrocarbon produces 1.76 g of \( \ce{CO2} \) and 0.72 g of \( \ce{H2O} \) on complete combustion. What is its molecular formula if its molar mass is 56 g/mol? (Atomic masses: C = 12, H = 1, O = 16)

Q8. How many significant figures are present in the result of \( \frac{0.0678 \times 310.15}{0.0821} \)?

Q9. What is the mass of \( \ce{AlCl3} \) produced when 13.5 g of \( \ce{Al} \) reacts with excess \( \ce{Cl2} \)? (Molar masses: Al = 27 g/mol, \( \ce{AlCl3} \) = 133.5 g/mol)

Q10. What is the mass of \( \ce{MgSO4} \) produced when 8.4 g of \( \ce{Mg(OH)2} \) reacts with excess \( \ce{H2SO4} \)? (Molar masses: \( \ce{Mg(OH)2} \) = 58 g/mol, \( \ce{MgSO4} \) = 120 g/mol)

NEET ChemistrySome Basic Concepts Of Chemistry

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A 0.25 M \( \ce{NaOH} \) solution is diluted by adding 300 mL of water to 200 mL of the original solution. What is the final molarity?

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About this NEET MCQ Test

This page provides a free online MCQ test for NEET Chemistry preparation, focusing specifically on the chapter Some Basic Concepts Of Chemistry. It contains 10 carefully selected multiple-choice questions (MCQs) designed to test your conceptual understanding and exam readiness.

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Key concepts covered in this specific test include Solution, Original, Molarity, Contains, Molecules, and Avogadro.

Taking these timed MCQ tests helps you simulate the real NEET exam environment. Detailed step-by-step explanations are provided for every question to help you learn from your mistakes and strengthen your fundamentals.

Preview of Questions in this Test

Q1. A 0.25 M \( \ce{NaOH} \) solution is diluted by adding 300 mL of water to 200 mL of the original solution. What is the final molarity?

  • A. 0.15 M
  • B. 0.05 M
  • C. 0.2 M
  • D. 0.1 M

Q2. A gas mixture contains 2 g of \( \ce{H2} \) and 16 g of \( \ce{O2} \). What is the total number of molecules? (Molar masses: \( \ce{H2} \) = 2 g/mol, \( \ce{O2} \) = 32 g/mol, Avogadro number = \( 6.022 \times 10^{23} \))

  • A. \( 6.022 \times 10^{23} \)
  • B. \( 9.033 \times 10^{23} \)
  • C. \( 3.011 \times 10^{23} \)
  • D. \( 12.044 \times 10^{23} \)

Q3. A compound contains 52.17% carbon, 13.04% hydrogen, and 34.78% oxygen by mass. What is its empirical formula? (Atomic masses: C = 12, H = 1, O = 16)

  • A. \( \ce{CH3O} \)
  • B. \( \ce{C2H6O} \)
  • C. \( \ce{C2H5O} \)
  • D. \( \ce{CH2O} \)

Q4. How many grams of \( \ce{Al2O3} \) are required to produce 5.4 g of \( \ce{Al} \) with excess \( \ce{CO} \)? (Molar masses: \( \ce{Al2O3} \) = 102 g/mol, Al = 27 g/mol)

  • A. 5.1 g
  • B. 20.4 g
  • C. 15.3 g
  • D. 10.2 g

Q5. What volume of \( \ce{O2} \) at STP is required to burn 6 g of \( \ce{CH4} \) completely to \( \ce{CO2} \) and \( \ce{H2O} \)? (Molar mass: \( \ce{CH4} \) = 16 g/mol)

  • A. 16.8 L
  • B. 8.4 L
  • C. 22.4 L
  • D. 33.6 L

+ 5 more questions in the actual test

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