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In $NO_{3}^{-}$ ion, the number of bond pair and lone pair of electrons on nitrogen atom are respectively:
The incorrect statement among the following regarding the molecules of $\text{CH}_4$, $\text{NH}_3$, and $\text{H}_2\text{O}$ is:
The hybridisations of atomic orbitals of nitrogen in $\text{NO}_2^+$, $\text{NO}_3^-$ and $\text{NH}_4^+$ are:
Dipole-induced dipole interactions are present in which of the following pairs?
Arrange the following species in increasing order of their dipole moments: $NH_3, NF_3, BF_3, H_2O$
Which pair of ions among the following list do not constitute an iso-electronic pair?
The tendency of $\text{BF}_3$, $\text{BCl}_3$, and $\text{BBr}_3$ to behave as Lewis acid decreases in the sequence:
Three moles of an ideal gas expanded spontaneously into vacuum. The work done will be:
Which statement about peptide bonds is NOT true?
In which of the following pairs, both the species are not isostructural?
Which of the following species contains equal number of $\sigma$ and $\pi$ bonds?
The electronegativity difference between $\text{N}$ and $\text{F}$ is greater than that between $\text{N}$ and $\text{H}$, yet the dipole moment of $\text{NH}_3$ (1.5 D) is larger than that of $\text{NF}_3$ (0.2 D). This is because:
The species, having bond angles of 120° is :
Match the molecules in List-I with the corresponding shape in List-II: List-I (Molecules): (a) $NH_3$ (b) $ClF_3$ (c) $PCl_5$ (d) $BrF_5$ List-II (Shape): (i) Square pyramidal (ii) Trigonal bipyramidal (iii) Trigonal pyramidal (iv) T-shape Choose the correct answer from the options given below:
Hydrolysis of sucrose is given by the following reaction. Sucrose + $H_2O \rightleftharpoons$ Glucose + Fructose. If the equilibrium constant ($K_c$) is $2 \times 10^{13}$ at 300 K, the value of $\Delta_r G^{\ominus}$ at the same temperature will be :
The hybridisations of atomic orbitals of nitrogen in NO$^+$, NO$_3^-$ and NH$_3$ respectively are:
Which of the following pairs of compounds is isoelectronic and isostructural?
The pair of electrons in the given carbanion, $\text{CH}_3\text{C}\equiv\text{C}^-$, is present in which of the following orbitals?
Match List-I with List-II. List-I: A. Coke, B. Diamond, C. Fullerene, D. Graphite. List-II: I. Carbon atoms are $sp^3$ hybridised, II. Used as a dry lubricant, III. Used as a reducing agent, IV. Cage like molecules. Choose the correct answer from the options given below:
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R: Assertion A: Metallic sodium dissolves in liquid ammonia giving a deep blue solution, which is paramagnetic. Reason R: The deep blue solution is due to the formation of amide. In the light of the above statements, choose the correct answer from the options given below: