Q1. How much heat is needed to convert \( 0.1 \, \text{kg} \) of mercury at \( -39^\circ \text{C} \) to liquid at \( 357^\circ \text{C} \)? (Specific heat of solid mercury = \( 140 \, \text{J kg}^{-1} \text{K}^{-1} \), latent heat of fusion = \( 0.12 \times 10^5 \, \text{J kg}^{-1} \), specific heat of liquid mercury = \( 140 \, \text{J kg}^{-1} \text{K}^{-1} \))
- A. 6.5 kJ
- B. 6.7 kJ
- C. 6.744 kJ
- D. 7 kJ