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NEET CHEMISTRYChemical KineticsEasy

Question

An increase in the concentration of the reactants of a reaction leads to a change in:

A

Heat of reaction

B

Threshold energy

C

Collision frequency

D

Activation energy

Step-by-Step Solution

According to the Collision Theory of chemical kinetics:

  1. Collision Frequency (ZZ): This is defined as the number of collisions per second per unit volume of the reaction mixture . When the concentration of reactants increases, the number of molecules per unit volume increases. Consequently, the probability of these molecules colliding with each other increases, leading to a direct increase in the collision frequency.
  2. Activation Energy (EaE_a) and Threshold Energy: These are energy barriers characteristic of the specific chemical reaction and its mechanism. They are affected by the presence of a catalyst (which provides an alternate path with lower EaE_a) but are independent of the concentration of reactants .
  3. Heat of Reaction (ΔH\Delta H): This is a thermodynamic state function determined by the difference in enthalpies of products and reactants. It does not change with concentration.

Therefore, increasing concentration increases the rate of reaction primarily by increasing the collision frequency.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Chemical Kinetics. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYChemical Kineticsincreaseconcentrationreactantsreactionchange

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If the half-life is independent of its initial concentration, then the order of the reaction is:

A.0
B.1
C.3
D.2
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Which quantity is altered when a catalyst is introduced during a chemical reaction?

A.Internal energy
B.Enthalpy
C.Activation energy
D.Entropy
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The rate of the reaction $2NO + Cl_2 \rightarrow 2NOCl$ is given by the rate equation $\text{rate} = k[NO]^2[Cl_2]$. The value of the rate constant can be increased by:

A.Increasing the concentration of $NO$
B.Increasing the concentration of $Cl_2$
C.Increasing the temperature
D.All of the above
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The rate of a first-order reaction is $1.5 \times 10^{-2} \text{ mol L}^{-1} \text{ min}^{-1}$ at $0.5 \text{ M}$ concentration of the reactant. The half-life of the reaction is:

A.23.1 min
B.8.73 min
C.7.53 min
D.0.383 min
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The activation energy of a reaction can be determined from the slope of the graph between:

A.$\ln k$ vs $T$
B.$\frac{\ln k}{T}$ vs $T$
C.$\ln k$ vs $\frac{1}{T}$
D.$\frac{T}{\ln k}$ vs $\frac{1}{T}$
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The plot of $\ln k$ vs $1/T$ for the following reaction, $2N_2O_5(g) \rightarrow 4NO_2(g) + O_2(g)$ gives a straight line with the slope of the line equal to $-1.0 \times 10^4 \text{ K}$. What is the activation energy for the reaction in $\text{J mol}^{–1}$? (Given: $R = 8.3 \text{ J K}^{–1} \text{ mol}^{–1}$)

A.$4.0 \times 10^2$
B.$4.0 \times 10^{-2}$
C.$8.3 \times 10^{-4}$
D.$8.3 \times 10^4$
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Consider the reaction $N_2(g) + 3H_2(g) \rightarrow 2NH_3(g)$. The equality relationship between $\frac{d[NH_3]}{dt}$ and $-\frac{d[H_2]}{dt}$ is:

A.\frac{d[NH_3]}{dt} = -\frac{1}{3}\frac{d[H_2]}{dt}
B.+\frac{d[NH_3]}{dt} = -\frac{2}{3}\frac{d[H_2]}{dt}
C.+\frac{d[NH_3]}{dt} = -\frac{3}{2}\frac{d[H_2]}{dt}
D.+\frac{d[NH_3]}{dt} = -\frac{d[H_2]}{dt}
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For a chemical reaction, $4A + 3B \rightarrow 6C + 9D$ rate of formation of C is $6 \times 10^{–2} \text{ mol L}^{–1} \text{ s}^{–1}$ and rate of disappearance of A is $4 \times 10^{–2} \text{ mol L}^{–1} \text{ s}^{–1}$. The rate of reaction and amount of B consumed in interval of 10 seconds, respectively will be:

A.$1 \times 10^{–2} \text{ mol L}^{–1} \text{ s}^{–1}$ and $30 \times 10^{–2} \text{ mol L}^{–1}$
B.$10 \times 10^{–2} \text{ mol L}^{–1} \text{ s}^{–1}$ and $10 \times 10^{–2} \text{ mol L}^{–1}$
C.$1 \times 10^{–2} \text{ mol L}^{–1} \text{ s}^{–1}$ and $10 \times 10^{–2} \text{ mol L}^{–1}$
D.$10 \times 10^{–2} \text{ mol L}^{–1} \text{ s}^{–1}$ and $30 \times 10^{–2} \text{ mol L}^{–1}$
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