At $27^\circ ext{C}$ latent heat of fusion of a compound is $2930 ext{ J/mol}$. Entropy change is:

Question

At $27^\circ	ext{C}$ latent heat of fusion of a compound is $2930	ext{ J/mol}$. Entropy change is:

Accepted Answer

The entropy change during phase transformation (fusion) is calculated using the formula:
$\Delta S_{	ext{fusion}} = \frac{\Delta H_{	ext{fusion}}}{T_f}$
Given:
Latent heat of fusion, $\Delta H_{	ext{fusion}} = 2930	ext{ J/mol}$
Temperature, $T_f = 27^\circ	ext{C} = 27 + 273 = 300	ext{ K}$
Substituting the values into the formula:
$\Delta S = \frac{2930	ext{ J/mol}}{300	ext{ K}} = 9.766	ext{ J/mol K} \approx 9.77	ext{ J/mol K}$

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