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NEET CHEMISTRYStructure of AtomMedium

Question

Consider the following sets of quantum numbers (n, l, m, s): (i) 3, 0, 0, +1/2 (ii) 2, 2, 1, +1/2 (iii) 4, 3, -2, -1/2 (iv) 1, 0, -1, -1/2 (v) 3, 2, 3, +1/2

Which of the following sets of quantum numbers is not possible?

A

ii, iii and iv

B

i, ii, iii and iv

C

ii, iv and v

D

i and iii

Step-by-Step Solution

We apply the selection rules for quantum numbers to determine validity:

  1. Principal Quantum Number (n): Integer > 0.
  2. Azimuthal Quantum Number (l): Integer where 0l<n0 \le l < n.
  3. Magnetic Quantum Number (m): Integer where lm+l-l \le m \le +l.

Evaluation of Sets:

  • (i) 3, 0, 0, +1/2: Valid (l=0<3l=0 < 3, m=0m=0). Corresponds to 3s.
  • (ii) 2, 2, 1, +1/2: Invalid. ll cannot equal nn (max ll for n=2n=2 is 1).
  • (iii) 4, 3, -2, -1/2: Valid (l=3<4l=3 < 4, 23|-2| \le 3). Corresponds to 4f.
  • (iv) 1, 0, -1, -1/2: Invalid. If l=0l=0, mm must be 0. m=1m=-1 is not allowed.
  • (v) 3, 2, 3, +1/2: Invalid. If l=2l=2, max mm is +2. m=3m=3 is not allowed.

Therefore, sets ii, iv, and v are not possible.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Structure of Atom. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYStructure of Atomconsiderfollowingquantumnumbersfollowing

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