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NEET CHEMISTRYThermodynamicsEasy

Question

Enthalpy of combustion of carbon to carbon dioxide is −390.0 kJ mol⁻¹. The amount of heat released when 35.0 g of CO2 is formed from the reaction of carbon and dioxygen gas, is:

A

310 kJ

B

490 kJ

C

245 kJ

D

700 kJ

Step-by-Step Solution

The combustion of carbon to form carbon dioxide is given by the reaction: C(s) + O₂(g) → CO₂(g); \Delta cH = −390.0 kJ mol⁻¹. This means that when 1 mole of CO₂ (which has a molar mass of 44 g) is formed, 390.0 kJ of heat is released. We need to find the heat released when 35.0 g of CO₂ is formed. Number of moles of CO₂ in 35.0 g = 35.0 g / 44 g mol⁻¹. Amount of heat released = (35.0 / 44) × 390.0 kJ = 310.22 kJ ≈ 310 kJ.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Thermodynamics. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYThermodynamicsenthalpycombustioncarboncarbondioxide

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