For a reaction $3A \rightarrow 2B$, the average rate of appearance of B is given by $\frac{\Delta [B]}{\Delta

Question

For a reaction $3A \rightarrow 2B$, the average rate of appearance of B is given by $\frac{\Delta [B]}{\Delta t}$. The correct relation between the average rate of appearance of B with the average rate of disappearance of A is:

Accepted Answer

For the given reaction $3A ightarrow 2B$, the rate of the reaction can be expressed in terms of the disappearance of reactant A and the appearance of product B as follows:
$	ext{Rate of reaction} = -\frac{1}{3}\frac{\Delta [A]}{\Delta t} = +\frac{1}{2}\frac{\Delta [B]}{\Delta t}$ 
To find the relation for the average rate of appearance of B, we rearrange the equation:
$\frac{\Delta [B]}{\Delta t} = -\frac{2}{3}\frac{\Delta [A]}{\Delta t}$

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