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NEET CHEMISTRYChemical KineticsEasy

Question

For the chemical reaction N2(g)+3H2(g)⇌2NH3(g)N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g), the correct option is:

A

3d[H2]dt=2d[NH3]dt3\frac{d[H_2]}{dt} = 2\frac{d[NH_3]}{dt}

B

−13d[H2]dt=−12d[NH3]dt-\frac{1}{3}\frac{d[H_2]}{dt} = -\frac{1}{2}\frac{d[NH_3]}{dt}

C

−d[N2]dt=2d[NH3]dt-\frac{d[N_2]}{dt} = 2\frac{d[NH_3]}{dt}

D

−d[N2]dt=12d[NH3]dt-\frac{d[N_2]}{dt} = \frac{1}{2}\frac{d[NH_3]}{dt}

Step-by-Step Solution

The rate of a chemical reaction is expressed in terms of the rate of change in concentration of any reactant or product, divided by its stoichiometric coefficient in the balanced chemical equation. For reactants, the rate is negative (disappearance), and for products, it is positive (appearance).

For the general reaction aA+bB→cC+dDaA + bB \rightarrow cC + dD, the rate is: Rate=−1ad[A]dt=−1bd[B]dt=+1cd[C]dt=+1dd[D]dt\text{Rate} = -\frac{1}{a}\frac{d[A]}{dt} = -\frac{1}{b}\frac{d[B]}{dt} = +\frac{1}{c}\frac{d[C]}{dt} = +\frac{1}{d}\frac{d[D]}{dt}

Applying this to the given reaction N2(g)+3H2(g)⇌2NH3(g)N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g): Rate=−d[N2]dt=−13d[H2]dt=+12d[NH3]dt\text{Rate} = -\frac{d[N_2]}{dt} = -\frac{1}{3}\frac{d[H_2]}{dt} = +\frac{1}{2}\frac{d[NH_3]}{dt}

Comparing the terms for N2N_2 and NH3NH_3: −d[N2]dt=+12d[NH3]dt-\frac{d[N_2]}{dt} = +\frac{1}{2}\frac{d[NH_3]}{dt}

This relationship indicates that the rate of consumption of nitrogen is half the rate of formation of ammonia .

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Chemical Kinetics. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYChemical Kineticschemicalreactionrightleftharpoonscorrectoption

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If the half-life is independent of its initial concentration, then the order of the reaction is:

A.0
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