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Identify the final product [D] obtained in the following sequence of reactions. CH3CHO→ii)H3O+i)LiAlH4[A]→H2SO4,Δ[B]→HBr[C]→Na/dryether[D]CH_3CHO \xrightarrow[ii) H_3O^+]{i) LiAlH_4} [A] \xrightarrow{H_2SO_4, \Delta} [B] \xrightarrow{HBr} [C] \xrightarrow{Na/dry ether} [D]

A
B
C
D

Step-by-Step Solution

  1. CH3CHOCH_3CHO reduced by LiAlH4LiAlH_4 gives ethanol [A]. 2. Ethanol dehydrated by H2SO4H_2SO_4 gives ethene [B]. 3. Ethene reacts with HBrHBr to give bromoethane [C]. 4. Bromoethane reacts with Na/dry ether (Wurtz reaction) to give butane [D].
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