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NEET CHEMISTRYEquilibriumMedium

Question

If 0.01 M0.01\text{ M} acetic acid solution is 1%1\% ionised, then pH of this acetic acid solution is:

A

3

B

2

C

4

D

1

Step-by-Step Solution

For a weak acid like acetic acid, the concentration of hydrogen ions (H+H^+) at equilibrium is given by the product of its initial concentration (cc) and its degree of ionization (α\alpha) .

Given: Concentration, c=0.01 M=102 Mc = 0.01\text{ M} = 10^{-2}\text{ M} Degree of ionization, α=1%=1100=102\alpha = 1\% = \frac{1}{100} = 10^{-2}

[H+]=cα=102×102=104 M[H^+] = c\alpha = 10^{-2} \times 10^{-2} = 10^{-4}\text{ M}

The pH of the solution is calculated as: pH=log[H+]\text{pH} = -\log[H^+] pH=log(104)=4\text{pH} = -\log(10^{-4}) = 4

Therefore, the pH of the given acetic acid solution is 44.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Equilibrium. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYEquilibriumaceticsolutionionisedaceticsolution

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