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NEET CHEMISTRYThermodynamicsEasy

Question

If C+O2CO2C + O_2 \rightarrow CO_2, C+12O2COC + \frac{1}{2}O_2 \rightarrow CO, and CO+12O2CO2CO + \frac{1}{2}O_2 \rightarrow CO_2, the heats of reaction are QQ, 12-12, and 10-10 respectively. Then QQ =

A

2-2

B

22

C

22-22

D

16-16

Step-by-Step Solution

According to Hess's law of constant heat summation, the enthalpy change for a reaction is the same whether it occurs in one step or in a series of steps. The overall reaction is: C+O2CO2(ΔH=Q)C + O_2 \rightarrow CO_2 \quad (\Delta H = Q) This can be obtained by adding the two intermediate steps: Step 1: C+12O2CO(ΔH1=12)C + \frac{1}{2}O_2 \rightarrow CO \quad (\Delta H_1 = -12) Step 2: CO+12O2CO2(ΔH2=10)CO + \frac{1}{2}O_2 \rightarrow CO_2 \quad (\Delta H_2 = -10) Adding Step 1 and Step 2 gives the overall reaction. Therefore, Q=ΔH1+ΔH2=12+(10)=22Q = \Delta H_1 + \Delta H_2 = -12 + (-10) = -22.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Thermodynamics. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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