In the neutral or faintly alkaline medium, $KMnO_4$ oxidises iodide into iodate. The change in oxidation state

Question

In the neutral or faintly alkaline medium, $KMnO_4$ oxidises iodide into iodate. The change in oxidation state of manganese in this reaction is from:

Accepted Answer

In a neutral or faintly alkaline medium, permanganate ($MnO_4^-$) oxidises iodide ($I^-$) to iodate ($IO_3^-$). The reaction is given as:
$2MnO_4^- + H_2O + I^- \rightarrow 2MnO_2 + 2OH^- + IO_3^-$
In this reaction, manganese is reduced from the +7 oxidation state in $MnO_4^-$ to the +4 oxidation state in $MnO_2$ .

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