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NEET CHEMISTRYSolutionsEasy

Question

KHK_H values for some gases at the same temperature 'T' are given: Gas : KHK_H/k bar Ar : 40.3 CO2CO_2 : 1.67 HCHO : 1.83×1051.83 \times 10^{-5} CH4CH_4 : 0.413 KHK_H is Henry's Law constant in water. The order of their solubility in water is :

A

Ar < CO2CO_2 < CH4CH_4 < HCHO

B

Ar < CH4CH_4 < CO2CO_2 < HCHO

C

HCHO < CO2CO_2 < CH4CH_4 < Ar

D

HCHO < CH4CH_4 < CO2CO_2 < Ar

Step-by-Step Solution

According to Henry's law, the partial pressure of a gas in vapour phase (pp) is proportional to the mole fraction of the gas (xx) in the solution, and is expressed as p=KHxp = K_H x. This implies that at a constant pressure, the higher the value of Henry's law constant (KHK_H), the lower is the solubility of the gas in the liquid .

Given KHK_H values: Ar = 40.3 kbar CO2CO_2 = 1.67 kbar CH4CH_4 = 0.413 kbar HCHO = 1.83×1051.83 \times 10^{-5} kbar

Since the decreasing order of KHK_H is Ar > CO2CO_2 > CH4CH_4 > HCHO, the increasing order of solubility will be the exact reverse: Ar < CO2CO_2 < CH4CH_4 < HCHO.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Solutions. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYSolutionsvaluestemperaturehenrysconstantsolubility

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