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NEET CHEMISTRYElectrochemistryMedium

Question

Match the redox conversions in List-I with the corresponding number of Faradays required in List-II.

List-I (Redox Conversion) A. 1 mol1\text{ mol} of H2O\text{H}_2\text{O} to O2\text{O}_2 B. 1 mol1\text{ mol} of MnO4−\text{MnO}_4^- to Mn2+\text{Mn}^{2+} C. 1.5 mol1.5\text{ mol} of Ca\text{Ca} from molten CaCl2\text{CaCl}_2 D. 1 mol1\text{ mol} of FeO\text{FeO} to Fe2O3\text{Fe}_2\text{O}_3

List-II (Number of Faraday required) I. 3F3\text{F} II. 2F2\text{F} III. 1F1\text{F} IV. 5F5\text{F}

A

A - III, B - IV, C - I, D - II

B

A - II, B - III, C - I, D - IV

C

A - III, B - IV, C - II, D - I

D

A - II, B - IV, C - I, D - III

Step-by-Step Solution

A. For the oxidation of 1 mol1\text{ mol} of H2O\text{H}_2\text{O} to O2\text{O}_2: H2O→12O2+2H++2e−\text{H}_2\text{O} \rightarrow \frac{1}{2}\text{O}_2 + 2\text{H}^+ + 2\text{e}^- 2 moles of electrons are involved, so 2 Faradays2\text{ Faradays} (2F2\text{F}) are required.

B. For the reduction of 1 mol1\text{ mol} of MnO4−\text{MnO}_4^- to Mn2+\text{Mn}^{2+}: MnO4−+8H++5e−→Mn2++4H2O\text{MnO}_4^- + 8\text{H}^+ + 5\text{e}^- \rightarrow \text{Mn}^{2+} + 4\text{H}_2\text{O} 5 moles of electrons are involved, so 5 Faradays5\text{ Faradays} (5F5\text{F}) are required.

C. For the reduction of 1.5 mol1.5\text{ mol} of Ca\text{Ca} from CaCl2\text{CaCl}_2: Ca2++2e−→Ca\text{Ca}^{2+} + 2\text{e}^- \rightarrow \text{Ca} To produce 1 mol1\text{ mol} of Ca\text{Ca}, 2F2\text{F} are required. To produce 1.5 mol1.5\text{ mol} of Ca\text{Ca}, 1.5×2 F=3 F1.5 \times 2\text{ F} = 3\text{ F} are required.

D. For the oxidation of 1 mol1\text{ mol} of FeO\text{FeO} to Fe2O3\text{Fe}_2\text{O}_3: Fe2+→Fe3++e−\text{Fe}^{2+} \rightarrow \text{Fe}^{3+} + \text{e}^- 1 mole of electrons is involved, so 1 Faraday1\text{ Faraday} (1F1\text{F}) is required.

Therefore, the correct matching is A - II, B - IV, C - I, D - III.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Electrochemistry. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYElectrochemistryconversionscorrespondingnumberfaradaysrequired

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