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NEET CHEMISTRYThe d-and f-Block ElementsMedium

Question

More number of oxidation states are exhibited by the actinoids than by the lanthanoids. The main reason for this is:

A

More energy difference between 5f and 6d orbitals than that between 4f and 5d orbitals

B

Lesser energy difference between 5f and 6d orbitals than that between 4f and 5d orbitals

C

Greater metallic character of the lanthanoids than that of the corresponding actinoids

D

More active nature of the actinoids

Step-by-Step Solution

Actinoids exhibit a larger number of oxidation states than lanthanoids because the 5f5f, 6d6d and 7s7s energy levels are of comparable energies (i.e., they have a lesser energy difference). This allows the electrons from all these subshells to participate in bonding and exhibit a wide range of oxidation states. In contrast, the energy difference between 4f4f and 5d5d orbitals in lanthanoids is relatively larger.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from The d-and f-Block Elements. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYThe d-and f-Block Elementsnumberoxidationstatesexhibitedactinoids

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