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NEET CHEMISTRYSolutionsEasy

Question

pAp_A and pBp_B are the vapour pressures of pure liquid components A and B, respectively, of an ideal binary solution. If xAx_A represents the mole fraction of component A, the total pressure of the solution will be:

A

pA+xA(pBpA)p_A + x_A(p_B - p_A)

B

pA+xA(pApB)p_A + x_A(p_A - p_B)

C

pB+xA(pBpA)p_B + x_A(p_B - p_A)

D

pB+xA(pApB)p_B + x_A(p_A - p_B)

Step-by-Step Solution

For an ideal binary solution containing components A and B, the partial vapour pressures according to Raoult's law are: PA=xApAP_A = x_A p_A PB=xBpBP_B = x_B p_B According to Dalton's law of partial pressures, the total pressure of the solution (PtotalP_{\text{total}}) is the sum of the partial pressures: Ptotal=PA+PB=xApA+xBpBP_{\text{total}} = P_A + P_B = x_A p_A + x_B p_B We know that the sum of mole fractions of all components in a solution is unity, i.e., xA+xB=1x_A + x_B = 1, which gives xB=1xAx_B = 1 - x_A. Substituting this into the total pressure equation: Ptotal=xApA+(1xA)pBP_{\text{total}} = x_A p_A + (1 - x_A) p_B Ptotal=xApA+pBxApBP_{\text{total}} = x_A p_A + p_B - x_A p_B Ptotal=pB+xA(pApB)P_{\text{total}} = p_B + x_A(p_A - p_B)

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Solutions. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYSolutionsvapourpressuresliquidcomponentsrespectively

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