back to directory
NEET ChemistryGeneralMedium

Question

The correct option for free expansion of an ideal gas under adiabatic condition is

A

q=0,ΔT=0q = 0, \Delta T = 0 and w=0w = 0

B

q=0,ΔT<0q = 0, \Delta T < 0 and w>0w > 0

C

q<0,ΔT=0q < 0, \Delta T = 0 and w=0w = 0

D

q>0,ΔT>0q > 0, \Delta T > 0 and w>0w > 0

Step-by-Step Solution

For free expansion, external pressure Pex=0P_{ex} = 0, so work w=PexΔV=0w = -P_{ex}\Delta V = 0. For an adiabatic process, q=0q = 0. By the first law of thermodynamics, ΔU=q+w=0\Delta U = q + w = 0. Since internal energy of an ideal gas depends only on temperature, ΔU=0\Delta U = 0 implies ΔT=0\Delta T = 0.

Exam Context & Concepts Covered

This question aligns with the NEET Chemistry syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

Chemistrycorrectoptionexpansionadiabaticcondition

More Chemistry Questions

View all

An increase in the concentration of the reactants of a reaction leads to change in

1.activation energy
2.heat of reaction
3.threshold energy
4.collision frequency
MediumSolve

For the reaction, $2\text{Cl}(g) \rightarrow \text{Cl}_2(g)$, the correct option is :

1.$\Delta_r\text{H} > 0$ and $\Delta_r\text{S} > 0$
2.$\Delta_r\text{H} > 0$ and $\Delta_r\text{S} < 0$
3.$\Delta_r\text{H} < 0$ and $\Delta_r\text{S} > 0$
4.$\Delta_r\text{H} < 0$ and $\Delta_r\text{S} < 0$
HardSolve

The freezing point depression constant ($K_f$) of benzene is 5.12 K kg $mol^{-1}$. The freezing point depression for the solution of molality 0.078 m containing a non-electrolyte solute in benzene is (rounded off upto two decimal places) :

A.0.20 K
B.0.80 K
C.0.40 K
D.0.60 K
MediumSolve

Identify the correct statements from the following: (a) $CO_2(g)$ is used as refrigerant for ice-cream and frozen food. (b) The structure of $C_{60}$ contains twelve six carbon rings and twenty five carbon rings. (c) ZSM-5, a type of zeolite, is used to convert alcohols into gasoline. (d) CO is colorless and odourless gas.

1.(a), (b) and (c) only
2.(a) and (c) only
3.(b) and (c) only
4.(c) and (d) only
MediumSolve

Identify the incorrect statement.

1.$\text{Cr}^{2+} (d^4)$ is a stronger reducing agent than $\text{Fe}^{2+} (d^6)$ in water.
2.The transition metals and their compounds are known for their catalytic activity due to their ability to adopt multiple oxidation states and to form complexes.
3.Interstitial compounds are those that are formed when small atoms like H, C or N are trapped inside the crystal lattices of metals.
4.The oxidation states of chromium in $\text{CrO}_4^{2-}$ and $\text{Cr}_2\text{O}_7^{2-}$ are not the same.
MediumSolve

HCl was passed through a solution of $CaCl_2$, $MgCl_2$ and $NaCl$. compound(s) crystallise(s)?

1.Both $MgCl_2$ and $CaCl_2$
2.Only $NaCl$
3.Only $MgCl_2$
4.$NaCl$, $MgCl_2$ and $CaCl_2$
MediumSolve

A tertiary butyl carbocation is more stable than a secondary butyl carbocation because of ?

1.$-I$ effect of $-CH_3$ groups
2.$+R$ effect of $-CH_3$ groups
3.$-R$ effect of $-CH_3$ groups
4.Hyperconjugation
MediumSolve

Hydrolysis of sucrose is given by the following reaction. Sucrose + $H_2O \rightleftharpoons$ Glucose + Fructose. If the equilibrium constant ($K_c$) is $2 \times 10^{13}$ at 300 K, the value of $\Delta_r G^{\ominus}$ at the same temperature will be :

1.$-8.314 \text{ J mol}^{-1} \text{K}^{-1} \times 300 \text{ K} \times \ln(2 \times 10^{13})$
2.$8.314 \text{ J mol}^{-1} \text{K}^{-1} \times 300 \text{ K} \times \ln(2 \times 10^{13})$
3.$8.314 \text{ J mol}^{-1} \text{K}^{-1} \times 300 \text{ K} \times \ln(3 \times 10^{13})$
4.$-8.314 \text{ J mol}^{-1} \text{K}^{-1} \times 300 \text{ K} \times \ln(4 \times 10^{13})$
MediumSolve

This neet chemistry practice question is part of the TopperSquare free question bank. TopperSquare offers 15,000+ chapter-wise NEET MCQs across Physics, Chemistry, and Biology with detailed step-by-step explanations, full mock tests, NEET PYQs (2010–2024), and an AI-powered performance analytics dashboard. browse all neet practice questions → · practice chemistry sets →