The equilibrium constant $K_p$ for the following reaction is:
$ ext{MgCO}_3(s) ightleftharpoons ext{MgO}(

Question

The equilibrium constant $K_p$ for the following reaction is:
$	ext{MgCO}_3(s) ightleftharpoons 	ext{MgO}(s) + 	ext{CO}_2(g)$

Accepted Answer

For a heterogeneous equilibrium involving pure solids and gases, the concentration or partial pressure of pure solids is taken as constant (or unity) .
The given reaction is:
$	ext{MgCO}_3(s) ightleftharpoons 	ext{MgO}(s) + 	ext{CO}_2(g)$
Since $	ext{MgCO}_3$ and $	ext{MgO}$ are pure solids, their partial pressures are not included in the equilibrium constant expression.
Therefore, $K_p = P_{	ext{CO}_2}$ .

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