The molar conductance of a solution, given its conductivity ($0.248 ext{ S m}^{–1}$) and concentration ($0.2\

Question

The molar conductance of a solution, given its conductivity ($0.248	ext{ S m}^{–1}$) and concentration ($0.2	ext{ mol m}^{–3}$) is:

Accepted Answer

Given:
Conductivity, $\kappa = 0.248	ext{ S m}^{-1}$
Concentration, $c = 0.2	ext{ mol m}^{-3}$

Molar conductivity ($\Lambda_m$) is given by the formula:
$\Lambda_m = \frac{\kappa}{c}$

Substituting the given values:
$\Lambda_m = \frac{0.248	ext{ S m}^{-1}}{0.2	ext{ mol m}^{-3}}$
$\Lambda_m = 1.24	ext{ S m}^2	ext{ mol}^{-1}$