The number of electrons delivered at the cathode during electrolysis by a current of $1 ext{ ampere}$ in $60

Question

The number of electrons delivered at the cathode during electrolysis by a current of $1 	ext{ ampere}$ in $60 	ext{ seconds}$ is (charge on electron = $1.60 	imes 10^{-19} 	ext{ C}$):

Accepted Answer

According to the definition of electric current, the total charge ($Q$) passed is the product of current ($I$) and time ($t$).
$Q = I 	imes t$
Given:
$I = 1 	ext{ A}$
$t = 60 	ext{ s}$
$Q = 1 	ext{ A} 	imes 60 	ext{ s} = 60 	ext{ C}$
The total charge is also equal to the number of electrons ($n$) multiplied by the charge of a single electron ($e$).
$Q = n 	imes e$
$n = \frac{Q}{e} = \frac{60 	ext{ C}}{1.60 	imes 10^{-19} 	ext{ C}}$
$n = 37.5 	imes 10^{19} = 3.75 	imes 10^{20}$
Therefore, the number of electrons delivered at the cathode is $3.75 	imes 10^{20}$.

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