Which of the following statement(s) is/are correct about the elimination reaction of 2-Bromopentane to form pe

Question

Which of the following statement(s) is/are correct about the elimination reaction of 2-Bromopentane to form pent-2-ene?
(a) $\beta$-Elimination reaction
(b) Follows Zaitsev rule
(c) Dehydrohalogenation reaction
(d) Dehydration reaction

Accepted Answer

1. **$\beta$-Elimination:** The reaction involves the removal of a hydrogen atom from the $\beta$-carbon (the carbon adjacent to the one holding the halogen) and the halogen from the $\alpha$-carbon. Hence, it is a $\beta$-elimination reaction .
2. **Zaitsev Rule:** In dehydrohalogenation, if more than one alkene can be formed, the major product is the more substituted alkene (Zaitsev product). For 2-bromopentane, pent-2-ene (more substituted) is the major product compared to pent-1-ene .
3. **Dehydrohalogenation:** The reaction entails the elimination of a hydrogen halide (HBr), so it is termed dehydrohalogenation .
4. **Dehydration:** This term specifically refers to the removal of a water molecule ($H_2O$), typically from alcohols (e.g., ethanol to ethene) . Since 2-bromopentane is a haloalkane, not an alcohol, this is not a dehydration reaction.

Therefore, statements (a), (b), and (c) are correct.

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