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NEET CHEMISTRYStructure of AtomMedium

Question

Which one is the wrong statement?

A

de-Broglie's wavelength is given by λ=h/mv\lambda = h/mv where m=m = mass of the particle, v=v = group velocity of the particle

B

The uncertainty principle is ΔEΔth/4π\Delta E \cdot \Delta t \ge h/4\pi

C

Half-filled and fully filled orbitals have greater stability due to greater exchange energy, greater symmetry and more balanced arrangement

D

The energy of 2s-orbital is less than the energy of 2p-orbital in case of hydrogen like atoms

Step-by-Step Solution

We analyze each statement:

  1. de-Broglie Wavelength: The equation λ=h/mv\lambda = h/mv correctly represents the wavelength of a matter wave. This is a correct statement.
  2. Uncertainty Principle: Heisenberg's uncertainty principle can be expressed in terms of energy and time as ΔEΔth4π\Delta E \Delta t \ge \frac{h}{4\pi}. This is a correct statement.
  3. Orbital Stability: As seen in transition elements (Source: Chemistry Class 12, Unit 4, Section 4.3.3), half-filled and fully filled orbitals exhibit extra stability due to high exchange energy and symmetrical distribution of electrons. This is a correct statement.
  4. Energy Levels in Hydrogen: For hydrogen-like atoms (single-electron systems), the energy of an orbital depends only on the principal quantum number (nn). Therefore, the energy of the 2s orbital is equal to the energy of the 2p orbital (E2s=E2pE_{2s} = E_{2p}). The statement that 2s<2p2s < 2p is true only for multi-electron atoms where shielding effects occur. Thus, this is the wrong statement.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Structure of Atom. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYStructure of Atomstatement

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In hydrogen atom, what is the de Broglie wavelength of an electron in the second Bohr orbit? [Given that Bohr radius, $a_0 = 52.9$ pm]

A.211.6 pm
B.211.6 $\pi$ pm
C.52.9 $\pi$ pm
D.105.8 pm
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Maximum number of electrons in a subshell with l = 3 and n = 4 is:

A.14
B.16
C.10
D.12
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If the principal quantum number n=6, the correct sequence of filling of electrons will be:

A.ns → np → (n-1)d → (n-2)f
B.ns → (n-2)f → (n-1)d → np
C.ns → (n-1)d → (n-2)f → np
D.ns → (n-2)f → np → (n-1)d
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The measurement of the electron position is associated with an uncertainty in momentum which is equal to $1 \times 10^{-18} \text{ g cm s}^{-1}$. The uncertainty in velocity of the electron will be: (mass of an electron is $9 \times 10^{-28} \text{ g}$)

A.1 × 10⁹ cm s⁻¹
B.1 × 10⁶ cm s⁻¹
C.1 × 10⁵ cm s⁻¹
D.1 × 10¹¹ cm s⁻¹
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What is the maximum number of orbitals that can be identified with the following quantum numbers? n = 3, l = 1, m = 0

A.1
B.2
C.3
D.4
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The relation between $n_m$ ($n_m$ = number of permissible values of magnetic quantum number, $m_l$) for a given value of azimuthal quantum number ($l$) is:

A.$n_m = l + 2$
B.$l = \frac{n_m - 1}{2}$
C.$l = 2n_m + 1$
D.$n_m = 2l^2 + 1$
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Which one of the following ions has electronic configuration [Ar]3d⁶? (At. no: Mn = 25, Fe = 26, Co = 27, Ni = 28)

A.Ni³⁺
B.Mn³⁺
C.Fe³⁺
D.Co³⁺
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How many electrons can fit in the subshell for which n = 3 and l = 1?

A.2
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