Question

A block of mass m is placed on a smooth

inclined wedge ABC of inclination  as shown

in the figure. The wedge is given an

acceleration 'a' towards the right. The

relation between a and  for the block to

remain stationary on the wedge is

Accepted Answer

In non-inertial frame,

$$N \sin 	heta = ma \quad \dots(i)$$

$$N \cos 	heta = mg \quad \dots(ii)$$

Dividing equation (i) by (ii), we get:
$$	an 	heta = \frac{a}{g}$$

$$a = g 	an 	heta$$