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A set of 'n' equal resistors, of value 'R' each,

are connected in series to a battery of emf

'E' and internal resistance 'R'. The current

drawn is I. Now, the 'n' resistors are

connected in parallel to the same battery.

Then the current drawn from battery becomes

10 I. The value of 'n' is

","answerCount":1,"acceptedAnswer":{"@type":"Answer","text":"

$I = nR$ ...(i)

\n\n

$E = 10 I + nR$ ...(ii)

\n\n

7. Dividing (ii) by (i),

\n\n

$$\\frac{(n + 1)R}{10} = 1 + \\frac{1}{n} R$$

\n\n

After solving the equation, $n = 10$

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