An inductor $20 ext{ mH}$, a capacitor $100 ext{ }\mu ext{F}$ and a resistor $50 ext{ }\Omega$ are conn

Question

An inductor $20 	ext{ mH}$, a capacitor $100 	ext{ }\mu	ext{F}$ and a resistor $50 	ext{ }\Omega$ are connected in series across a source of emf, $V = 10 \sin 314 	ext{ t}$. The power loss in the circuit is

Accepted Answer

$P_{av} = \left( \frac{V_{RMS}}{Z} ight)^2 R$. $Z = \sqrt{R^2 + \left( \omega L - \frac{1}{\omega C} ight)^2} = 56 	ext{ }\Omega$. Therefore, $P_{av} = \left( \frac{10}{(\sqrt{2}) 56} ight)^2 	imes 50 = 0.79 	ext{ W}$.

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