Consider the change in oxidation state of Bromine corresponding to different emf values as shown in the diagra

Question

Consider the change in oxidation state of Bromine corresponding to different emf values as shown in the diagram below: $	ext{BrO}_4^- \xrightarrow{1.82 	ext{V}} 	ext{BrO}_3^- \xrightarrow{1.5 	ext{V}} 	ext{HBrO}$ and $	ext{Br}^- \xleftarrow{1.0652 	ext{V}} 	ext{Br}_2 \xleftarrow{1.595 	ext{V}} 	ext{HBrO}$. Then the species undergoing disproportionation is

Accepted Answer

For $	ext{HBrO} ightarrow 	ext{Br}_2$, $E^\circ = 1.595 	ext{V}$. For $	ext{HBrO} ightarrow 	ext{BrO}_3^-$, $E^\circ = 1.5 	ext{V}$. $E^\circ_{	ext{cell}}$ for the disproportionation of $	ext{HBrO} = E^\circ_{	ext{HBrO/Br}_2} - E^\circ_{	ext{BrO}_3^-/	ext{HBrO}} = 1.595 - 1.5 = 0.095 	ext{V} = +	ext{ve}$. Hence, $	ext{HBrO}$ undergoes disproportionation.

Step-by-Step Solution

Practice All general Questions