Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations: a.

Question

Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations: a. $60	ext{ mL } \frac{M}{10} 	ext{ HCl} + 40	ext{ mL } \frac{M}{10} 	ext{ NaOH}$ b. $55	ext{ mL } \frac{M}{10} 	ext{ HCl} + 45	ext{ mL } \frac{M}{10} 	ext{ NaOH}$ c. $75	ext{ mL } \frac{M}{5} 	ext{ HCl} + 25	ext{ mL } \frac{M}{5} 	ext{ NaOH}$ d. $100	ext{ mL } \frac{M}{10} 	ext{ HCl} + 100	ext{ mL } \frac{M}{10} 	ext{ NaOH}$ pH of which one of them will be equal to 1?

Accepted Answer

For option (c): Meq of HCl = $75 	imes \frac{1}{5} 	imes 1 = 15$. Meq of NaOH = $25 	imes \frac{1}{5} 	imes 1 = 5$. Meq of HCl in resulting solution = $15 - 5 = 10$. Molarity of $[H^+]$ in resulting mixture = $\frac{10}{100} = \frac{1}{10}$. pH = $-\log[H^+] = -\log[\frac{1}{10}] = 1.0$.

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