The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA

Question

The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance

Accepted Answer

Energy stored in inductor $U = \frac{1}{2}LI^2$. Given $U = 25 	imes 10^{-3} 	ext{ J}$ and $I = 60 	imes 10^{-3} 	ext{ A}$. Substituting values: $25 	imes 10^{-3} = \frac{1}{2} 	imes L 	imes (60 	imes 10^{-3})^2$. Solving for $L$: $L = \frac{25 	imes 2 	imes 10^6 	imes 10^{-3}}{3600} = \frac{500}{36} = 13.89 	ext{ H}$.

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