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NEET generalGeneralHard

Question

The solubility of BaSO4BaSO_4 in water is 2.42×10−3 gL−12.42 \times 10^{-3} \text{ gL}^{-1} at 298 K. The value of its solubility product (KspK_{sp}) will be (Given molar mass of BaSO4=233 g mol−1BaSO_4 = 233 \text{ g mol}^{-1})

A

1.08×10−14 mol2L−21.08 \times 10^{-14} \text{ mol}^2 \text{L}^{-2}

B

1.08×10−12 mol2L−21.08 \times 10^{-12} \text{ mol}^2 \text{L}^{-2}

C

1.08×10−10 mol2L−21.08 \times 10^{-10} \text{ mol}^2 \text{L}^{-2}

D

1.08×10−8 mol2L−21.08 \times 10^{-8} \text{ mol}^2 \text{L}^{-2}

Step-by-Step Solution

Solubility of BaSO4BaSO_4, s=2.42×10−3233 (mol L−1)=1.04×10−5 (mol L−1)s = \frac{2.42 \times 10^{-3}}{233} \text{ (mol L}^{-1}) = 1.04 \times 10^{-5} \text{ (mol L}^{-1}). BaSO4(s)⇌Ba2+(aq)+SO42−(aq)BaSO_4(s) \rightleftharpoons Ba^{2+}(aq) + SO_4^{2-}(aq). Ksp=[Ba2+][SO42−]=s2=(1.04×10−5)2=1.08×10−10 mol2L−2K_{sp} = [Ba^{2+}][SO_4^{2-}] = s^2 = (1.04 \times 10^{-5})^2 = 1.08 \times 10^{-10} \text{ mol}^2 \text{L}^{-2}.

Exam Context & Concepts Covered

This question aligns with the NEET general syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

generalsolubilitysolubilityproduct

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