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NEET generalGeneralHard

Question

The solubility of BaSO4BaSO_4 in water is 2.42×10−3 gL−12.42 \times 10^{-3} \text{ gL}^{-1} at 298 K. The value of its solubility product (KspK_{sp}) will be (Given molar mass of BaSO4=233 g mol−1BaSO_4 = 233 \text{ g mol}^{-1})

A

1.08×10−14 mol2L−21.08 \times 10^{-14} \text{ mol}^2 \text{L}^{-2}

B

1.08×10−12 mol2L−21.08 \times 10^{-12} \text{ mol}^2 \text{L}^{-2}

C

1.08×10−10 mol2L−21.08 \times 10^{-10} \text{ mol}^2 \text{L}^{-2}

D

1.08×10−8 mol2L−21.08 \times 10^{-8} \text{ mol}^2 \text{L}^{-2}

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NEET general: "The solubility of $BaSO_4$ in water is $2.42 \times 10^{-3} \text{ gL}^{-1}$ at 298 K. The value of its solubility produ..." — Solved MCQ | TopperSquare