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NEET PHYSICSThermal Properties of MatterMedium

Question

A copper rod of 88 cm88 \text{ cm} and an aluminium rod of an unknown length have an equal increase in their lengths independent of an increase in temperature. The length of the aluminium rod is: (αCu=1.7×105 K1\alpha_{\text{Cu}} = 1.7 \times 10^{-5} \text{ K}^{-1} and αAl=2.2×105 K1\alpha_{\text{Al}} = 2.2 \times 10^{-5} \text{ K}^{-1})

A

68 cm68 \text{ cm}

B

6.8 cm6.8 \text{ cm}

C

113.9 cm113.9 \text{ cm}

D

88 cm88 \text{ cm}

Step-by-Step Solution

Let the initial length of the copper rod be LCuL_{\text{Cu}} and that of the aluminium rod be LAlL_{\text{Al}}. The increase in length of the copper rod for a temperature rise of ΔT\Delta T is given by: ΔLCu=LCuαCuΔT\Delta L_{\text{Cu}} = L_{\text{Cu}} \alpha_{\text{Cu}} \Delta T The increase in length of the aluminium rod for the same temperature rise is: ΔLAl=LAlαAlΔT\Delta L_{\text{Al}} = L_{\text{Al}} \alpha_{\text{Al}} \Delta T It is given that the increase in their lengths is equal, irrespective of the increase in temperature. Therefore: ΔLCu=ΔLAl\Delta L_{\text{Cu}} = \Delta L_{\text{Al}} LCuαCuΔT=LAlαAlΔTL_{\text{Cu}} \alpha_{\text{Cu}} \Delta T = L_{\text{Al}} \alpha_{\text{Al}} \Delta T LCuαCu=LAlαAlL_{\text{Cu}} \alpha_{\text{Cu}} = L_{\text{Al}} \alpha_{\text{Al}} Substituting the given values (LCu=88 cmL_{\text{Cu}} = 88 \text{ cm}, αCu=1.7×105 K1\alpha_{\text{Cu}} = 1.7 \times 10^{-5} \text{ K}^{-1}, αAl=2.2×105 K1\alpha_{\text{Al}} = 2.2 \times 10^{-5} \text{ K}^{-1}): 88×1.7×105=LAl×2.2×10588 \times 1.7 \times 10^{-5} = L_{\text{Al}} \times 2.2 \times 10^{-5} LAl=88×1.72.2=88×1722=4×17=68 cmL_{\text{Al}} = \frac{88 \times 1.7}{2.2} = \frac{88 \times 17}{22} = 4 \times 17 = 68 \text{ cm}.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Thermal Properties of Matter. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSThermal Properties of Mattercopperaluminiumunknownlengthincrease

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