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NEET PHYSICSWave OpticsEasy

Question

A linearly polarized monochromatic light of intensity 10 lumen is incident on a polarizer. The angle between the direction of polarization of the light and that of the polarizer such that the intensity of output light is 2.5 lumen is:

A

60°

B

75°

C

30°

D

45°

Step-by-Step Solution

  1. Identify Given Values:
  • Incident Intensity (I0I_0) = 10 lumen (Correcting typo '101010').
  • Transmitted/Output Intensity (II) = 2.5 lumen (Correcting typo '2.52.52.5').
  1. Formula: According to Malus' Law, when linearly polarized light is incident on a polarizer, the transmitted intensity is given by: I=I0cos2θI = I_0 \cos^2 \theta where θ\theta is the angle between the direction of polarization of the incident light and the pass axis of the polarizer.
  2. Calculation: 2.5=10cos2θ2.5 = 10 \cos^2 \theta cos2θ=2.510=14=0.25\cos^2 \theta = \frac{2.5}{10} = \frac{1}{4} = 0.25 Taking the square root: cosθ=0.5\cos \theta = 0.5 θ=cos1(0.5)=60\theta = \cos^{-1}(0.5) = 60^\circ
  3. Conclusion: The angle must be 6060^\circ.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Wave Optics. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSWave Opticslinearlypolarizedmonochromaticintensityincident

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