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NEET PHYSICSCURRENT ELECTRICITYMedium

Question

A silver wire has a resistance of 2.1 \Omega at 27.5°C, and a resistance of 2.7 \Omega at 100°C. The temperature coefficient of resistivity of silver is:

A

0.0033°C⁻¹

B

0.039°C⁻¹

C

0.0039°C⁻¹

D

0.033°C⁻¹

Step-by-Step Solution

According to the NCERT text (Exercise 3.5), the relationship between resistance and temperature is given by R2=R1[1+α(T2−T1)]R_2 = R_1 [1 + \alpha (T_2 - T_1)]. Rearranging for the temperature coefficient α\alpha: α=R2−R1R1(T2−T1)\alpha = \frac{R_2 - R_1}{R_1(T_2 - T_1)}. Given: R1=2.1 ΩR_1 = 2.1 \ \Omega at T1=27.5∘CT_1 = 27.5^\circ\text{C} R2=2.7 ΩR_2 = 2.7 \ \Omega at T2=100∘CT_2 = 100^\circ\text{C} Substituting the values: α=2.7−2.12.1(100−27.5)=0.62.1×72.5=0.6152.25≈0.0039 ∘C−1\alpha = \frac{2.7 - 2.1}{2.1 (100 - 27.5)} = \frac{0.6}{2.1 \times 72.5} = \frac{0.6}{152.25} \approx 0.0039 \ ^\circ\text{C}^{-1} , .

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from CURRENT ELECTRICITY. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSCURRENT ELECTRICITYsilverresistanceresistancetemperaturecoefficient

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