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NEET PHYSICSWAVEEasy

Question

A transverse wave propagating along the xx-axis is represented by: y(x,t)=8.0sin(0.5πx4πtπ4)y(x,t) = 8.0\sin(0.5\pi x - 4\pi t - \frac{\pi}{4}), where xx is in meters and tt in seconds. The speed of the wave is:

A

4π m/s4\pi \text{ m/s}

B

0.5 m/s0.5 \text{ m/s}

C

π4 m/s\frac{\pi}{4} \text{ m/s}

D

8 m/s8 \text{ m/s}

Step-by-Step Solution

The given wave equation is y(x,t)=8.0sin(0.5πx4πtπ4)y(x,t) = 8.0\sin(0.5\pi x - 4\pi t - \frac{\pi}{4}). Comparing this with the standard travelling wave equation y(x,t)=Asin(kxωt+ϕ)y(x,t) = A\sin(kx - \omega t + \phi), we get: Angular wave number, k=0.5π rad/mk = 0.5\pi \text{ rad/m} Angular frequency, ω=4π rad/s\omega = 4\pi \text{ rad/s} The speed of the wave vv is given by the formula: v=ωkv = \frac{\omega}{k} v=4π0.5π=8 m/sv = \frac{4\pi}{0.5\pi} = 8 \text{ m/s}.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from WAVE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSWAVEtransversepropagatingrepresentedfracpimeters

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