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NEET PHYSICSWAVE OPTICSEasy

Question

A wave travelling in the positive x-direction having maximum displacement along y-direction as 1 m1 \text{ m}, wavelength 2π m2\pi \text{ m} and frequency of 1/π Hz1/\pi \text{ Hz} is represented by

A

y=sin(x2t)y=\sin(x-2t)

B

y=sin(2πx2πt)y=\sin(2\pi x-2\pi t)

C

y=sin(10πx20πt)y=\sin(10\pi x-20\pi t)

D

y=sin(2πx+2πt)y=\sin(2\pi x+2\pi t)

Step-by-Step Solution

  1. Identify the given parameters: Maximum displacement (Amplitude), A=1 mA = 1 \text{ m}; Wavelength, λ=2π m\lambda = 2\pi \text{ m}; Frequency, f=1π Hzf = \frac{1}{\pi} \text{ Hz}.
  2. Calculate wave number (kk): The wave number is given by k=2πλk = \frac{2\pi}{\lambda}. k=2π2π=1 m1k = \frac{2\pi}{2\pi} = 1 \text{ m}^{-1}
  3. Calculate angular frequency (ω\omega): The angular frequency is given by ω=2πf\omega = 2\pi f. ω=2π×1π=2 rad/s\omega = 2\pi \times \frac{1}{\pi} = 2 \text{ rad/s}
  4. Formulate the wave equation: The general equation for a progressive wave travelling in the positive x-direction is y=Asin(kxωt)y = A \sin(kx - \omega t) or y=Asin(ωtkx)y = A \sin(\omega t - kx) . Substituting the calculated values into the first form: y=1sin(1x2t)=sin(x2t)y = 1 \cdot \sin(1 \cdot x - 2 \cdot t) = \sin(x - 2t)

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from WAVE OPTICS. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSWAVE OPTICStravellingpositivexdirectionhavingmaximum

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