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NEET PHYSICSThermodynamicsMedium

Question

During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its temperature. The ratio of CP/CVC_P/C_V for the gas is equal to:

A

4/34/3

B

22

C

5/35/3

D

3/23/2

Step-by-Step Solution

For an adiabatic process, the relation between pressure (PP) and temperature (TT) is given by P1γTγ=constantP^{1-\gamma}T^\gamma = \text{constant}, which can be rewritten as PTγγ1P \propto T^{\frac{\gamma}{\gamma-1}}. Given that PT3P \propto T^3. Equating the powers of TT, we get: γγ1=3\frac{\gamma}{\gamma - 1} = 3 γ=3γ3\gamma = 3\gamma - 3 2γ=3    γ=322\gamma = 3 \implies \gamma = \frac{3}{2} Since the ratio of specific heats CPCV=γ\frac{C_P}{C_V} = \gamma, the value is 32\frac{3}{2}.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Thermodynamics. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSThermodynamicsduringadiabaticprocesspressureproportional

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